Refrigeration Plant Operator B Practice Test

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What is the pressure exerted on a hydraulic plunger with an area of 0.10 m² and a force of 200 N?

1.64 kPa
750 Pa
1.84 kPa
2 kPa

The correct answer is: 2 kPa

To determine the pressure exerted on a hydraulic plunger, one would use the formula for pressure, which is defined as the force applied divided by the area over which that force is distributed. In this case, the force is 200 N and the area is 0.10 m². Calculating the pressure involves the following steps: 1. **Apply the formula**: Pressure (P) = Force (F) / Area (A) 2. **Substitute the given values**: P = 200 N / 0.10 m² 3. **Perform the calculation**: P = 2000 N/m² (which is equivalent to 2000 Pa) 4. To express this in kilopascals, recognize that 1 kPa = 1000 Pa, thus 2000 Pa = 2 kPa. This computation leads to the result of 2 kPa, which indicates the amount of pressure exerted on the hydraulic plunger due to the applied force over the specified area. Understanding these calculations is crucial for anyone studying hydraulics in refrigeration systems, as proper pressure management is essential in ensuring efficient system operation.